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Homework Help
Posted: Fri Jan 13, 2006 4:31 am
by Kills On Site
Well just slid back into algebra, as Algebra II now. Doing pretty well, reviewing now, but this one homework problem is stumping me and it really shouldn't be. Hope the answer comes to someone. The problem is, you havea farm with 40 animals total. On this farm you have chickens and cows, the total leg count is 100. What equation could be set up to solve for this?
Posted: Fri Jan 13, 2006 4:35 am
by Guest
100 = x + y
40 = x/4 + y/2
x: # of cow legs
y: # of chicken legs
The answers are:
40 cow legs = 10 cows
60 chicken legs = 30 chickens
Posted: Fri Jan 13, 2006 4:38 am
by werldhed
c = cows
h = chickens (hens, i guess)
c + h = 40
2(2c + h) = 100
Now substitute...
h = 40 - c, therefore...
2(2c + 40 - c) = 100
c + 40 = 50
c = 10
h = 30
Posted: Fri Jan 13, 2006 4:39 am
by Guest
By the way, I solved it with a matrix, sorry
Posted: Fri Jan 13, 2006 4:41 am
by werldhed
I just wanted to make myself feel better about math, since I was having such a time with that other one.
Posted: Fri Jan 13, 2006 4:49 am
by Guest
Yeah, nothing like crushing easy problems
Posted: Fri Jan 13, 2006 4:56 am
by Kills On Site
Thanks guys, I had a slight fuckup and thought I could solve it with a single equation, forgot about substitution. I remember doing this back in Algebra/Trig freshman year, and prolly Algebra I in 8th grade. Just needed the refresher, thanks again.
Posted: Fri Jan 13, 2006 5:03 am
by Guest
No problem, calculus is more fun though
Posted: Fri Jan 13, 2006 6:54 am
by menkent
ToxicBug wrote:No problem, calculus is more fun though
yea, have fun with that linear algebra II. i'm SO glad i've wiped all that crap out of my brain. :icon29: