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Another math problem.
Posted: Thu Dec 01, 2005 7:47 pm
by Deji
From destination A a bicycle left to point B. At the same time a motorcycle left from point B to point A. When the motorcycle had traversed 1/3 of the way, the bicycle still had 26km to go. When the bicycle had traversed 1/3 of the way, the motorcycle had 5km to go.Ffind the distance between the 2 points.
I've been at it from all angles, mainly using speed and distance and then trying to cancel out the speeds, but it all leads to nonsense answers, like 12.095. Help?
Posted: Thu Dec 01, 2005 8:00 pm
by Survivor
It's always bigger than 26 km but something seems missing
Posted: Thu Dec 01, 2005 8:12 pm
by phantasmagoria
Don't you need the speed of at least one of the objects?
Posted: Thu Dec 01, 2005 8:17 pm
by Deji
phantasmagoria wrote:Don't you need the speed of at least one of the objects?
That's what I thought, but apparently not. It's one of the harder questions for a 12th grade math exam.
Posted: Thu Dec 01, 2005 8:37 pm
by mad
this looks like a pretty simple question but i have forgotten all my mechanic maths
Posted: Thu Dec 01, 2005 9:16 pm
by rgoer
Hellchick is pretty smart, and she says it's 30km.
Posted: Thu Dec 01, 2005 10:19 pm
by MKJ
i think that answer wont cut it though, you usually have to tell them why its x
"the answer is 30km. i asked on the internet and hellchick (who's pretty smart cause she used to run PQ) says so"
Posted: Thu Dec 01, 2005 10:56 pm
by hax103
MKJ wrote:i think that answer wont cut it though, you usually have to tell them why its x
"the answer is 30km. i asked on the internet and hellchick (who's pretty smart cause she used to run PQ) says so"
Ahh, good ole algebra...
its prolly something like
d = distance between A and B
v = velocity of motorcycle
t = time for motorcycle to traverse 1/3 distance
u = velocity of bicycle
s = time for bicycle to traverse 1/3 distance
(d/3) = v * t
d-26 = u * t
(d/3) = u * s
d-5 = v * s
I'd assume after solving for s and t, iit works out to a quadratic equation for d
Posted: Fri Dec 02, 2005 12:06 am
by Sanction
(D-26)/3 = (D-5)/3
D=21
I think.
Posted: Fri Dec 02, 2005 12:12 am
by Zyte
the bicycle still had 26km to go.
Posted: Fri Dec 02, 2005 12:42 am
by menkent
assuming constant velocities, the ratio of distance traveled will be constant regardless of time. x(t1)/y(t1) = x(t2)/y(t2)
Posted: Fri Dec 02, 2005 1:07 am
by hax103
cool. it was a quadratic for d and hellchicky was right!
now lets suppose that the bicyclist is accelerating uniformly from 0.95c to 0.99c
menkent wrote:
assuming constant velocities, the ratio of distance traveled will be constant regardless of time. x(t1)/y(t1) = x(t2)/y(t2)
Posted: Fri Dec 02, 2005 1:23 am
by Guest
I think I found 33KM
Posted: Fri Dec 02, 2005 1:43 am
by andyman
It's like 20 minutes away man
Posted: Fri Dec 02, 2005 1:44 am
by Dark Metal
pete wrote:I think I found 33KM
Har har.
Posted: Fri Dec 02, 2005 4:42 am
by menkent
that some sort of french joke?
Posted: Fri Dec 02, 2005 5:49 am
by [xeno]Julios
hax103 wrote:cool. it was a quadratic for d and hellchicky was right!
now lets suppose that the bicyclist is accelerating uniformly from 0.95c to 0.99c
must add that to my creative suicide methods. (attempting to solve the problem, not accelerating to 0.99 c
)
Posted: Fri Dec 02, 2005 5:58 am
by mrd
Fuckin homework3world :\
Posted: Fri Dec 02, 2005 10:05 am
by MKJ
mrd wrote:Fuckin homework3world :\
at least he tried it before asking us
unlike toxigfag who's just like "yea i gotta write a thesis for tomorrow about [subject]. tell me all you know"
Posted: Fri Dec 02, 2005 11:11 am
by zewulf
Another vote for 30km :icon30: