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Having troubles grasping subneting.
Posted: Tue Sep 20, 2005 10:12 pm
by Iccy (temp)
Anyone knowledgeable?
I understand the classes and the first octate/decimal identifier. But breaking down the subnetting i just can seem to grasp. I need to understand the methods of calculating a availible ip range within a subnet. Like in a ip of 203.192.53.0. I cant seem to figure out the equations.
Can anyone help, this is driving me nuts.
Posted: Tue Sep 20, 2005 10:17 pm
by duffman91
What exactly do you not understand? Do you know how to get started? Have you checked google? The topic is heavily covered in all kinds of websites.
http://ou800doc.caldera.com/en/NET_tcpi ... uters.html
Posted: Tue Sep 20, 2005 10:20 pm
by R00k
Have you studied ANDing yet? That explains it all at a very basic level.
You can also download SolarWinds Subnet Calculator to help you understand and test with.
Aside from that, can you be a little more specific?
Posted: Tue Sep 20, 2005 11:19 pm
by plained
well first wipe the grease off your mits
then start out all soothie like as to get it all calmed , then coax it all clser with nice sounds, then grab -on real fast
ok
Posted: Tue Sep 20, 2005 11:21 pm
by tnf
yea bitwise ands.
Posted: Tue Sep 20, 2005 11:47 pm
by Tormentius
Posted: Wed Sep 21, 2005 12:06 am
by bork[e]
If you look at any, check this one out. very nice imo.
Posted: Wed Sep 21, 2005 12:31 am
by andyman
just try to think 'a net within a net' and you'll be fine
Posted: Wed Sep 21, 2005 1:06 am
by +JuggerNaut+
andyman wrote:just try to think 'a net within a net' and you'll be fine
ffs

Posted: Wed Sep 21, 2005 1:44 am
by Iccy (temp)
Well to start i was really lost cause iin the online stuff they wrote exponential numbers like this . 2x -2 = subnet. Basicly it made me try to figure out how 23 - 2 = 6 lol. Yea i was lost.
Now i been pouring over a cisco book, the sybex book, the learning to subnet site and another tutorial i found. So far this one makes the most sense to me.
http://www.pantz.org/networking/tcpip/subnetchart.shtml
Basicly i undestand the 3 classes, a/b/c. I understand the binary translation of a 8 bit or 1 byte network address. Where im getting stuck is understanding and implimenting the calculations needed to figure out the number of networks i can subnet.
ok, 198.132.123.34.
How do i figure out what available for this. This is what i know so far.
being a ip thats 192+ this puts it into class c which means that our binary data is in the 34 since the class C configuration is net.net.net.node.
now the 32 needs to be broke to binary right? If this is true then the binary subnet if im not mistaken is 11111111.11111111.11111111.00100010
Ok now im losing it. I know that 2x - 2 = the subnet. x = the number of bits used.
So if x = bits then the bits = 2, so 2x2 = 4 - 2 = 2, so i have 2 subnets available?
If so then 2 equates to 128+64 = 192.
So 198.132.123.34 = 198.132.123.34/192
Am i even close so far?
Posted: Wed Sep 21, 2005 1:48 am
by Iccy (temp)
R00k wrote:Have you studied ANDing yet? That explains it all at a very basic level.
You can also download SolarWinds Subnet Calculator to help you understand and test with.
Aside from that, can you be a little more specific?
I dont know what anding is so ill say no.
Does my post above help clarify my difficulties?
Posted: Wed Sep 21, 2005 4:39 am
by R00k
I typed a long post here, but it's been so long since I've worked with nuts and bolts of subnetting I was afraid I'd tell you wrong.
This, sir, is all you need:
http://www.ralphb.net/IPSubnet/
If you have a hard time understanding after reading that, come back and ask some specific questions.
